In this article, we will provide important questions for class 8 maths chapter 7 – Cubes and Cube Roots. These questions are prepared with reference to **NCERT book** as per **CBSE syllabus (2021-22)** The problems are provided with solutions here to make students prepare for exams and score good marks in their final exam.

The chapter-cubes and cube roots will comprise of finding the cubes & cube roots of numbers. We will also solve word problems based on this concept here.

## Important Questions With Solutions For Maths Class 8 Chapter 7 (Cubes and Cube Roots)

**Q.1: Find the cube of 3.5.**

Solution: 3.53 = 3.5 x 3.5 x 3.5

= 12.25 x 3.5

= 42.875

**Q.2: Is 392 a perfect cube? If not, find the smallest natural number by which 392 should be multiplied so that the product is a perfect cube.**

Solution: The prime factorisation of 392 gives:

392 = 2 x 2 x 2 x 7 x 7

Since, we can see, number 7 cannot be paired in a group of three. Therefore, 392 is not a perfect cube.

To make it a perfect cube, we have to multiply the 7 by the original number.

Thus,

2 x 2 x 2 x 7 x 7 x 7 = 2744, which is a perfect cube, such as 23 x 73 or 143.

Hence, the smallest natural number which should be multiplied to 392 to make a perfect cube is 7.

**Q.3: Find the smallest number by which 128 must be divided to obtain a perfect cube.**

Solution: The prime factorisation of 128 gives:

128 = 2×2×2×2×2×2×2

Now, if we group the factors in triplets of equal factors,

128 = (2×2×2)×(2×2×2)×2

Here, 2 cannot be grouped into triples of equal factors.

Therefore, we will divide 128 by 2 to get a perfect cube

**Q.4: Parikshit makes a cuboid of plasticine of sides 5 cm, 2 cm, 5 cm. How many such cuboids will he need to form a cube?**

Solution:

Given, side of the cube is 5 cm, 2 cm and 5 cm.

Therefore, volume of cube = 5×2×5 = 50

The prime factorisation of 50 = 2×5×5

Here, 2, 5 and 5 cannot be grouped into triples of equal factors.

Therefore, we will multiply 50 by 2×2×5 = 20 to get perfect square.

Hence, 20 cuboid is needed.

**Q.5: Find the cube root of 13824 by prime factorisation method.**

Solution:

First let us prime factorise 13824:

13824 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3

= 23 × 23 × 23 × 33

3√13824 = 2 × 2 × 2 × 3 = 24

**Q.6: Find the cube root of 17576 through estimation.**

Solution:

The given number is 17576.

Step 1: Form groups of three digits starting from the rightmost digit.

- Here, one group has three digits i.e., 576 whereas the other group has only two digits i.e.,17.

Step 2: Take 576.

- The digit 6 is at its one’s place.
- We will take here the one’s place of the required cube root as 6.

Step 3: Take the other group, i.e., 17.

- Cube of number 2 is 8 and cube of number 3 is 27.
- 17 lies between 8 and 27.
- The smaller number between 2 and 3 is 2.
- The one’s place of 2 is 2 itself.
- Now, take digit 2 as ten’s place of the required cube root.

Hence, the cube root of 17576 is;

3√17576 = 26

**Q.7: You are told that 1,331 is a perfect cube. Can you guess without factorisation what is its cube root? Similarly, guess the cube roots of 4913, 12167, 32768.**

Solution:

**By grouping the digits, we get 1 and 331**

Since, the unit digit of cube is 1, the unit digit of cube root is 1.

Therefore, we get 1 as the unit digit of the cube root of 1331.

The cube of 1 matches with the number of the second groups.

Therefore, the ten’s digit of our cube root is taken as the unit place of the smallest number.

We know that the unit’s digit of the cube of a number having digit as unit’s place 1 is 1.

Therefore, ∛1331 = 11

**By grouping the digits, we get 4 and 913**

We know that, since the unit digit of the cube is 3, the unit digit of the cube root is 7.

Therefore, we get 7 as unit digit of the cube root of 4913.

We know 13 = 1 and 23 = 8 , 1 > 4 > 8.

Thus, 1 is taken as ten-digit of the cube root. Therefore, ∛4913 = 17

**By grouping the digits, we get 12 and 167.**

Since the unit digit of the cube is 7, the unit digit of the cube root is 3.

Therefore, 3 is the unit digit of the cube root of 12167

We know 23 = 8 and 33 = 27, 8 > 12 > 27.

Thus, 2 is taken as the tenth digit of the cube root.

Therefore, ∛12167= 23

**By grouping the digits, we get 32 and 768.**

Since, the unit digit of the cube is 8, the unit digit of the cube root is 2.

Therefore, 2 is the unit digit of the cube root of 32768.

We know 33 = 27 and 43 = 64 , 27 > 32 > 64.

Thus, 3 is taken as ten-digit of the cube root.

Therefore, ∛32768= 32

### Class 8 Maths Chapter 7 Extra Questions

- Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube.
- 72
- 675

- Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube
- 81
- 192

- Find the cube root of 8000.
- Find the cube root of each of the following numbers by prime factorisation method.
- 91125
- 110592

- State true or false.
- Cube of any odd number is even.
- A perfect cube does not end with two zeros.
- If the square of a number ends with 5, then its cube ends with 25.
- There is no perfect cube which ends with 8.
- The cube of a two-digit number may be a three-digit number.
- The cube of a two-digit number may have seven or more digits.
- The cube of a single-digit number may be a single-digit number.

6. What number do you get when you multiply your number by three times?

(a)Square numbers

(b) Perfect numbers

(c) Cube numbers

7. Which of these is not a perfect cube?

(a) 1000

(b) 1728

(c)100